Subject: [PATCH v3 01/13] bisect--helper: convert `vocab_*` char pointers to char arrays

From: Miriam Rubio <[email-masked]>
Date: Sat, 8 Feb 2020 10:06:52 +0100

Instead of using a pointer that points at a constant string,
just give name directly to the constant string; this way, we
do not have to allocate a pointer variable in addition to
the string we want to use.

Let's convert `vocab_bad` and `vocab_good` char pointers to char arrays.

Mentored-by: Christian Couder <[email-masked]>
Signed-off-by: Miriam Rubio <[email-masked]>
---
 builtin/bisect--helper.c | 4 ++--
 1 file changed, 2 insertions(+), 2 deletions(-)

diff --git a/builtin/bisect--helper.c b/builtin/bisect--helper.c
index 1718df7f09..36c09b7238 100644
--- a/builtin/bisect--helper.c
+++ b/builtin/bisect--helper.c
@@ -52,8 +52,8 @@ static void set_terms(struct bisect_terms *terms, const char *bad,
 	terms->term_bad = xstrdup(bad);
 }
 
-static const char *vocab_bad = "bad|new";
-static const char *vocab_good = "good|old";
+static const char vocab_bad[] = "bad|new";
+static const char vocab_good[] = "good|old";
 
 /*
  * Check whether the string `term` belongs to the set of strings
-- 
2.25.0