Subject: Re: Difference between --date-order and reverse chronological order?

From: Johannes Sixt <[email-masked]>
Date: Wed, 27 Apr 2011 21:39:50 +0200

Am 27.04.2011 19:36, schrieb Junio C Hamano:
> Dun Peal <[email-masked]> writes:
> 
>> But by Git's definition, for a child commit to be created, its parent
>> must already exist. So even in reverse chronological order, all
>> parents should come after all their children, no?
> 
> I think "distributed" and "your clock may be skewed" would solve that
> puzzlement ;-)

Are you saying that given this history:

      E----D
    /     /
   A--B--C

* we can get D-C-B-E-A or D-E-C-B-A with --topo-order

* we can get the above plus D-C-E-B-A with --date-order

* and with neither --topo-order nor --date-order we can also get
D-E-A-C-B or D-C-B-A-E if there was sufficient clock skew when the
commits were created. How would such a clock skew have looked like?

-- Hannes