Subject: Re: Request feature: –no-submodule

From: Taylor Blau <[email-masked]>
Date: Wed, 2 Jun 2021 16:31:04 -0400

On Wed, Jun 02, 2021 at 01:31:11PM +0300, Ilias Apostolou wrote:
> Hello Git community.
>
> As you already know, git ls-files command lists all of the tracked files,
> but submodule names are included.
>
> My team would like a –no-submodule switch to exclude those.

In all honesty, though this seems like a niche request for ls-files to
fulfill, ls-files already has quite the collection of options, so I
wouldn't be sad to see it learn how to do this, too.

The change boils down to having builtin/ls-files.c:show_ce() avoid
printing out submoudles in when '--exclude-submoudles' is given).
Something like this:

--- >8 ---

diff --git a/builtin/ls-files.c b/builtin/ls-files.c
index 45cc3b23dd..09d76fd068 100644
--- a/builtin/ls-files.c
+++ b/builtin/ls-files.c
@@ -35,6 +35,7 @@ static int show_fsmonitor_bit;
 static int line_terminator = '\n';
 static int debug_mode;
 static int show_eol;
+static int exclude_submodules;
 static int recurse_submodules;
 static int skipping_duplicates;

@@ -230,6 +231,9 @@ static void show_ce(struct repository *repo, struct dir_struct *dir,
 	if (max_prefix_len > strlen(fullname))
 		die("git ls-files: internal error - cache entry not superset of prefix");

+	if (exclude_submodules && S_ISGITLINK(ce->ce_mode))
+		return;
+
 	if (recurse_submodules && S_ISGITLINK(ce->ce_mode) &&
 	    is_submodule_active(repo, ce->name)) {
 		show_submodule(repo, dir, ce->name);
@@ -662,6 +666,8 @@ int cmd_ls_files(int argc, const char **argv, const char *cmd_prefix)
 		OPT_SET_INT_F(0, "full-name", &prefix_len,
 			      N_("make the output relative to the project top directory"),
 			      0, PARSE_OPT_NONEG),
+		OPT_BOOL(0, "exclude-submodules", &exclude_submodules,
+			N_("avoid showing submodules altogether")),
 		OPT_BOOL(0, "recurse-submodules", &recurse_submodules,
 			N_("recurse through submodules")),
 		OPT_BOOL(0, "error-unmatch", &error_unmatch,

--- 8< ---

I'll leave it at that to decide if others think this is a good idea or
not.

Thanks,
Taylor